Easy
1 point
ID: #19338
Question
What voltage drop will be there across a 1kW flood light whose resistance when hot is 40
Options
1
100V
Correct Answer
2
50V
Correct Answer
3
150V
Correct Answer
4
200V
Correct Answer
Explanation
Power P = V²/R. বা, V² = P × R. এখানে P = 1000W, R = 40 ohm. V² = 1000 × 40 = 40000. সুতরাং, V = sqrt(40000) = 200V. তাই ভোল্টেজ ড্রপ হবে ২০০ ভোল্ট।